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Parachute Running Chute
What net retarding force must be supplied to chute to stop car in a distance of 1240 m? Answer in units of N.?
Given: g=9.81 m/s2.
The parachute on a race car that weighs 8920 N opens at the end of a quarter mile run when the car is traveling 35 m/s. Answer in units of N.
Use work-KE theorem.
W = ΔKE
W = F * d
So do this:
1/2mvf^2 - 1/2mvi^2 = F *d
divide 8920 by g to obtain the mass m. Then let
vi = 35 m/s
vf = 0
d = 1240 m
You have all the variables to solve for the Force here.
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Proper Speed Parachute Technique and Posture
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Tags: art, chute, dance, inspiration, parachute, parachute running chute, photo, photography | 
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